stivali ugg Any solution must saliva theoretical s

Any solution must saliva theoretical shock model and calculation method

District theoretical solution model Ⅳ (, delete. A (Ⅳ ¨ stables where there is only one on the independent variables z and a dependent variable. It is clear that new mathematical model. Whether it is from the number of variables or the dependent variable, with the original basic equation compared. are greatly reduced. and. model variables and parameters exclusively expressed in dimensionless form, which is conducive to pure mathematical model. so, rectifiable general solution model, in chart form is given to for future reference purposes. 3 model and example Method 3.1.1 3l solution that partition of the sectional shape of a transcript and calculate the cross section features deposited deposited first according to a transcript of breach by equation (5), (6) and (7) calculation and a, then Dam burst characteristic numbers obtained K, C and d and section of the slope break point at the corresponding depth value. must be pointed out, C in addition h. by definition, the partition of C (15) except for the District of C values are not calculated in this specific instance method see below. ll8 Sichuan Taiwan Union University (Engineering Science Edition), Volume 3, the evolution of water from the mechanical shock 3.12 Calculation 1) to determine the initial downstream water depth upstream water depth h h the districts, by type ( Cool

Find Ⅳ 0 and 2.) estimated shock evolution of the districts in water depth. 3) by (20) solved by equation ( Cool

Find h. Here it must be pointed out that equation (20) for solving elliptic integral term involving goods [, the solution method see [2,4]. 4) Check whether the estimates obtained by the h partition. That is transferred to (5); not,[link widoczny dla zalogowanych], repeat (1) to (3) steps. 5) The calculation of the amount of shock symptoms. Hydraulic gradient flow area 3.13 Calculation 1) to determine the range of z gradient flow region. 2) by (21) to solve any of the gradient flow zone. 27, and then calculate the amount of other water features. Draw 3.14 3.2 dimensionless flood hydrograph example shown in Figure 2 breach to section shape, for example, set burst fracture morphology parameters: Ml1 = 12. M2 = 08. Ml3 = 10, hil = 160m, hlz = 26.0m, Mrl = 1.3, Mr2 = 0.6, Mr3 = 10, Mr4 = 0.8, hrl = 10.0m, hr2 = 220m. hr3 = 30.0m bottom width of 6 = 20.0m, the upstream water depth hI} = 340m, following river water depth h = 3.4m,[link widoczny dla zalogowanych], find the instantaneous dam break after the collapse of the whole volume of the hydraulic characteristics and the mapping of flood line. Solution: Lower the water, the dam will collapse the whole transient generated in the downstream river water shock. 3.2.1 Blown 13 \The breach is divided into 10 + J0-1 = 6 small area. 3.2.2 Calculation of the number of transcripts, \except for the calculation of c does not use its definition formula. 1) When h: h0 = 34.0m, the water line in 6 district, port =, = Po, K = K6. from ( Cool

is solvable have w ≈ 1.O73O, according to equation (15), a c = 0o to c into (21),[link widoczny dla zalogowanych], where only z is unknown at this time, which can solve for z values corresponding to h0 z '≈ A 08071, This z is the dimensionless coordinate upstream of the weak discontinuity z. 2) When h: hr: 30.0m, the water line belongs to Area 6 and 5 of the area, two cases: n) belongs to Area 6. At this point , I = 3,[link widoczny dla zalogowanych], J = 4.q: port 6. sound = sound 6, K = K6.c = c. Ⅳ ≈ 1.0070. the above values into (21). can be solved by the corresponding h = 300m The z ≈ a 0.6137. b) belong to Zone 5, this time, I = 3, J = 3.q = Port 5: Sound 5, KK5.C = c, Ⅳ ≈ 21164. the above values into equation (21). the continuity of z, which corresponds to the same depth h on z only, so z: a 0.6137. At this point,[link widoczny dla zalogowanych], where only c is unknown, can be solved in Area 5, c ≈ 04214. Similarly, the district can be obtained by other cross-section c-value and depth of the slope break point corresponding to the z value. as shown in Table 1. 3.2.3 Evolution of area calculation by the shock wave type (2O) obtained Evolution of the shock zone W = 0.6136. Thus, from ( Cool

yields h = 13.4769m. DPRK Huang Guofu, etc. 2: Any transition must saliva stimulated theoretical model and calculation method of solution 1, Section 119, the partition table parameters bit Tab.1Va] ttesforCh ~ racteri3ticp ~ metersofdifferentcr. 5s-sectionedpartJtiorhs to obtain the w and the corresponding, K, C, and the known w0 on behalf of the A (21) type, can be obtained gradually

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